Number triangle

Q. Write a c program for following number structure :

1

22

333

4444

55555

4444

333

22

1

Ans.

/*c program for above triangle structure using while*/

#include<stdio.h>

#include<conio.h>

int main()

{

 int num,n,r=1,c;

 printf("Enter triangle number : ");

 scanf("%d",&num);

 while(num >= r)

 {

  c=1;

  while(c <= r)

  {

    printf("%d",r);

    c++;

  }

  printf("
");

  r++;

 }

 n=num-1;

 while(n >= 1)

 {

   c=1;

   while(c <= n)

   {

     printf("%d",n);

     c++;

   }

   printf("
");

   n--;

 }
 getch();

 return 0;

}

OR

/*c program for above number triangle using for loop*/

#include<stdio.h>

#include<conio.h>

int main()

{

 int num,n,r,c;

 printf("Enter triangle number : ");

 scanf("%d",&num);
 for(r=1; r<=num; r++)
 {
   for(c=1; c<=r; c++)
      printf("%d",r);
   printf("
");
 }
 for(n=num-1; n>=1; n--)
 {
   for(c=1; c<=n; c++)
      printf("%d",n);
   printf("
");
 }
 return 0;
}

Output :-

Enter triangle number :5

1

22

333

4444

55555

4444

333

22

1

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